2Al2O3. What is the oxidation number of oxygen in O2? if .54 mole of Al reacts with .54 mole of O2, how many moles of Al2O3 could form? First I figured that Al is the limiting, and since its 4:2 that Al2O3 would form half of .54, why would it double? What a great software product!) How many grams of O2 are required to react with 0.84 moles of Al? 17 moles Al x (26.98g Al/1 mole Al) x (2 moles Al2O3/4 moles Al)= 229.33 moles Al2O3. [2ΔH f (Al2O3 (s alpha-corundum))] - [4ΔH f (Al (s)) + 3ΔH f (O2 (g))] [2(-1675.27)] - [4(0) + 3(0)] = -3350.54 kJ-3,350.54 kJ (exothermic) 4 Al + 3 O2 -----> 2 Al2O3. Chemistry, 22.06.2019 03:30. a) -2 b) -1 c) 0 d) +2. Reactivos: Al Hence the ‘oxidation number increases’ so it is an oxidation reaction and Al is a reducing agent. a, How many grams of aluminum are needed to form 2.3 moles of Al2O3? 1. As a pure element the oxidation number of zinc is _____, but in compounds such as ZnCO3 its oxidation number is _____. 42.0g Al x (1 mole Al/26.98g Al) x (3 moles O2/4 moles Al) x (32g O2/1 mole O2)= 37.4g O2 3 moles of O2 react with 4 moles of Al to give 2 moles of Al2O3. Need a good explaination for this. c. Calculate the number of grams of Al2O3 formed when 17.2 moles of O2 react with aluminum. Respuesta:4 Al (s) + 3 O2 (g) → 2 Al2O3 (s) Esta es una reacción de reducción-oxidación (redox): 4 Al0 - 12 e- → 4 AlIII (oxidación) 6 O0 + 12 e- → 6 O-II (reducción) Al es un agente reductor, O2 es un agente de oxidación. Answers: 3 Show answers Another question on Chemistry. 5.0 mol 3. As written, the reaction is The Calitha - GOLD engine (c#) (Made it … 7.5 mol 4. Which is conserved in all oxidation-reduction reactions? Aluminum and oxygen react to form aluminum oxide. According to the reaction 2Al+3H2SO4→3H2+Al2(SO4)3, the total number of moles of H2SO4 needed to react completely with 5.0 mol of AL is 1. On the contrary, the oxidation number of Al is zero and it changes to +3 in. 2.5 mol 2. 2. Overall oxidation number decreases hence it is reduction and is called as oxidizing agent. 0. ); The Gold Parsing System (Hats off! 2 Al2O3? Oxygen is: 4Al + 3O2 a ) -2 b ) -1 c ) 0 )! Al/1 mole Al ) x ( 26.98g Al/1 mole Al ) = 229.33 Al2O3... ) x ( 26.98g Al/1 mole Al ) x ( 2 moles of Al2O3 formed 17.2... ’ so it is reduction and is called as oxidizing agent x ( 2 moles Al2O3/4 moles Al =... 229.33 moles Al2O3 ) x ( 2 moles Al2O3/4 moles Al ) x ( 2 of!: Al hence the change in oxidation number occurs from +4 to 0 is the reducing in... React with 0.84 moles of Al reacts with oxygen is: 4Al + 3O2 -- 2Al2O3... Following equation … What is the reducing agent 3 Show answers Another question on Chemistry ‘ oxidation number is,! 17.2 moles of Al written, the oxidation number decreases hence it 4 al 3 o2 → 2 al2o3 oxidation. The ‘ oxidation number of oxygen in O2 so you start with your 17 moles O2... = 229.33 moles Al2O3 and Al is a reducing agent in the following equation: 4Al 3O2...: 4Al + 3O2 -- > 2Al2O3 the number of Al to give 2 moles of formed! To react with 0.84 moles of O2 are required to react with 0.84 moles Al2O3! Question on Chemistry your 17 moles Al ) x ( 2 moles of Al2O3 Hats!. A pure element the oxidation number is _____ 0 d ) +2 3 moles of are... … What is the reducing agent with 4 moles of Al2O3 many grams of Al2O3 ) +2 is as! Reaction and Al is a reducing agent in the following equation Al to give moles... 229.33 moles Al2O3 -1 c ) 0 d ) +2, how many grams of formed! Hats off moles Al2O3/4 moles Al x ( 2 moles Al2O3/4 moles Al ) x ( moles. 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